Ex 26: Advanced Dictionary Challenges

Problem​

Building complex data structures often requires nesting comprehensions or working with heterogeneous data. Complete the following three advanced tasks:

1. List of Dicts to Map: Given a list of dictionaries (representing people), build a single dictionary of name -> age.
2. Factor Map: Build a dictionary where keys are numbers 1–10 and values are their corresponding factor lists.
3. Unique Evens: Flatten a nested list of numbers and keep only the unique even values, producing a set in a single expression.

Rules​

• For Task 1, use: people = [{"name": "alice", "age": 25}, {"name": "bob", "age": 30}, {"name": "carol", "age": 22}].
• For Task 3, use: [[1, 2, 3], [4, 5, 6], [2, 4, 8], [7, 9, 10]].

Boilerplate​

Copy below code and paste to our IDE for head start.

# Task 1: Name -> Age Map
people = [
    {"name": "alice", "age": 25},
    {"name": "bob", "age": 30},
    {"name": "carol", "age": 22},
]
name_age_map = {}

# Task 2: Factor Map (1-10)
factor_map = {}

# Task 3: Unique Evens
nested = [[1, 2, 3], [4, 5, 6], [2, 4, 8], [7, 9, 10]]
even_set = {}

Expected output​

{'alice': 25, 'bob': 30, 'carol': 22}
{1: [1], 2: [1, 2], 3: [1, 3], 4: [1, 2, 4], 5: [1, 5], 6: [1, 2, 3, 6], 7: [1, 7], 8: [1, 2, 4, 8], 9: [1, 3, 9], 10: [1, 2, 5, 10]}
{2, 4, 6, 8, 10}

Solution​

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# 1. Name -> Age Map
people = [{"name": "alice", "age": 25}, {"name": "bob", "age": 30}, {"name": "carol", "age": 22}]
name_age_map = {p["name"]: p["age"] for p in people}

# 2. Factor Map (1-10)
factor_map = {n: [i for i in range(1, n + 1) if n % i == 0] for n in range(1, 11)}

# 3. Unique Evens
nested = [[1, 2, 3], [4, 5, 6], [2, 4, 8], [7, 9, 10]]
even_set = {num for sublist in nested for num in sublist if num % 2 == 0}