Ex 11: Age Verification
Problem
We’re building a system to verify user age for access. The input will come as a string, which we must convert to a number before checking.
Rules
- Define
verify_age(age_str: str) -> str. - Convert the string to an integer using
int(). - Return "Access Granted" if the age is 18 or older.
- Otherwise return "Access Denied".
Boilerplate
Copy below code and paste to our IDE for head start.
# Write our code inside this function
def verify_age(age_str: str) -> str:
pass # remove this
# Call with test data
print(verify_age("20"))
print(verify_age("16"))
Expected Output
Access Granted
Access Denied
Solution
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Show solution
def verify_age(age_str: str) -> str:
age = int(age_str)
return "Access Granted" if age >= 18 else "Access Denied"
# Test calls
print(verify_age("20"))
print(verify_age("16"))
Details
Using a ternary expression here ("Access Granted" if age >= 18 else "Access Denied") is the most Pythonic way to handle a simple binary choice. It keeps the logic on a single line without sacrificing readability.